How could I sort an array of objects taking into account another array?
Example:
let sortArray = [90, 1000, 4520]
let notSortArrayObject = [ { id: 4520, value: 4 }, {id: 1000, value: 2}, {id: 90, value:10} ]
So I want an array equal notSortArrayObject but sortered by sortArray value
let sortArrayObject =[{id: 90, value:10} , {id: 1000, value: 2}, { id: 4520, value: 4 }]
Here's an approach. For each number in the "guide" array, find a match in the not sorted and add it to the sortedObjectArray. Note that this ignores any values which don't have matches in the other array.
var sortedObjectArray: [Object] = [] // whatever your object type is
for num in sortArray {
if let match = notSortArrayObject.first(where: {$0.id == num}) {
sortedObjectArray.append(match)
}
}
If you just want to sort by the id in ascending order, it's much simpler:
let sorted = notSortArrayObject.sorted(by: {$0.id < $1.id})
I noticed that sortArray is already sorted - you could just sort notSortArrayObject by id, but I assume that's not the point of what you're looking for.
So, let's say that sortArray = [1000, 4520, 90] (random order), to make things more interesting.
You can iterate through sortArray and append the values that match the id to sortArrayObject.
// To store the result
var sortArrayObject = [MyObject]()
// Iterate through the elements that contain the required sequence
sortArray.forEach { element in
// Add only the objects (only one) that match the element
sortArrayObject += notSortArrayObject.filter { $0.id == element }
}
let sorted = notSortArrayObject.sorted(by: { sortArray.firstIndex(of: $0.id) ?? Int.max < sortArray.firstIndex(of: $1.id) ?? Int.max })should do the trick