Check if element exists on page and continue if not using python [duplicate]

Question

Trying to resolve an issue where I need to check if an element is on a page if it exists then perform a piece of code if not then continue with script. The issue I have is that if the element does not appear then script fails with 'Failed to find element'

What I currently have is:

form_error = s.driver.find_element_by_xpath("//div[contains(@class,'screen-new-error')]")
form_error = form_error.get_attribute('textContent')
form_error = form_error[6:].strip()
             
if form_error == "There was a problem with the Form":
   result = "FAIL"
else:
  result = "PASS"

What does get_attribute do? Maybe something needs to be changed there. — Devang Sanghani
– Devang Sanghani, Commented Feb 1, 2022 at 11:59

Tal Folkman · Accepted Answer · 2022-02-01 12:02:12Z

1

you have a few options:

1.

from selenium.common.exceptions import NoSuchElementException        
def check_exists_by_xpath(xpath):
    try:
        webdriver.find_element_by_xpath(xpath)
    except NoSuchElementException:
        return False
    return True

call find_element inside a try/catch

answered Feb 1, 2022 at 12:02

Tal Folkman

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