Find object by key in array of object

Question

Hello this is array of objects

  const raceId = '1004'
  const array =  [
    {
      '1004': { brackets: { '18': [Object], '19': [Object], '20': [Object] } }
    },
    {
      '999': { brackets: { '1': [Object], '2': [Object], '3': [Object] } }
    }
  ]

So i am trying to return just a

{ brackets: { '18': [Object], '19': [Object], '20': [Object] } }

I have tried to use reduce(), map(), find() but not getting desired output. For example i have tried.

const reduced = raceScoringConfigGroups.reduce((acc, key) => {
   if (Object.keys(key)[0] === raceId) {
     return key[raceId]
   }
  }, {})

But for some reason getting undefined, can someone help me just a little bit, not sure what i am doing wrong. I don't like solutions with forEach or for loops, trying to write oneliner.

Barmar · Accepted Answer · 2022-01-20 17:08:27Z

2

The value you return in the reduce() callback is used as the accumulator in the next iteration. Since you don't return anything when the key doesn't match raceId, your code will only work if the matching key is the last element of the array.

Use find() rather than reduce(), and then get the property from that.

const found = raceScoringConfigGroups.find(el => el[raceId]);
const reduced = found?.[raceId];

answered Jan 20, 2022 at 17:08

Barmar

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Comments

Ali Konuk · Accepted Answer · 2022-01-20 17:07:04Z

0

Can you try this?

const result = array.filter(el => Object.keys(el) === raceId)[0];

answered Jan 20, 2022 at 17:07

Ali Konuk

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Comments

GianL · Accepted Answer · 2022-01-20 17:17:49Z

0

Well to a certain extent it is working as a loop because if you put a console.log before the return key[raceId] you will see that it first returns a value and then undefined.

I don't know if it's close to what you want to do but this is a way to find the object too

const findIt = array.find( item => Object.keys(item)[0] === raceId);
console.log(findIt)
console.log(findIt['1004'])

answered Jan 20, 2022 at 17:17

GianL

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