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This will print out 10+ links, how do I limit it to only fetch the first 3 links?

def getlinks(self):
        self.driver.get('https://www.youtube.com/results?search_query=iphone&sp=EgQIBRAB')

        the_links = self.driver.find_elements(By.ID, "video-title")
        sleep(5)

        for link in the_links:
            self.links.append(link.get_attribute('href'))

        for link in self.links:
            print(link)
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  • you point directly to index positon of the link using : for link in self.links[:3] Commented Dec 29, 2021 at 6:36

1 Answer 1

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Try for link in self.links[:3].

You can also use the equivalent expression for link in self.links[0:3].

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