OUTER_LIST=(1 2)
INNER_LIST=(a b)
for (( i=0; i < ${#OUTER_LIST[@]}; i++ )); do
echo "outer...${OUTER_LIST[$i]}"
for (( i=0; i < ${#INNER_LIST[@]}; i++ )); do
echo "inner...${INNER_LIST[$i]}"
done
done
Output:
outer...1
inner...a
inner...b
Question: why does it loop OUTER_LIST only 1 time ?
You use the same loop variable, i, in the inner loop so when that is done the first time, i will be 2 which is out of the range of the outer loop.
Fix it by using a different variable:
#!/bin/bash
OUTER_LIST=(1 2)
INNER_LIST=(a b)
for (( i=0; i < ${#OUTER_LIST[@]}; i++ )); do
echo "outer...${OUTER_LIST[$i]}"
for (( j=0; j < ${#INNER_LIST[@]}; j++ )); do
echo "inner...${INNER_LIST[$j]}"
done
done
Alternatively:
for outer in "${OUTER_LIST[@]}"; do
echo "outer...$outer"
for inner in "${INNER_LIST[@]}"; do
echo "inner...$inner"
done
done
Output:
outer...1
inner...a
inner...b
outer...2
inner...a
inner...b
