it is possible to not increment count in for loop in case an error happen, like this example
for i in range(10):
try:
print(i)
except: # if and error happen in i == 5 the next iteration will be 5 not 6
pass
I want to repeat the same iteration when the error happen. And thanks in advance.
When you use for...in there's no way to avoid going to the next item in the iteration when the loop repeats.
You can use a nested loop to keep trying with the same value of i until you don't get an error:
for i in range(10):
while True:
try:
print(i)
break
except:
pass
Since Python's for loop is technically a foreach loop you should use a while instead of for for more control.
i = 0
while i<10:
try:
#Do stuf
i += 1
except:
pass
If an error happens before i += 1 it will not be incremented.
Maybe wrap all into a while loop:
for i in range(10):
while True
try:
# whatever you have to do
print(i)
break
except:
pass
range()if you want more control over how it increments.for loopin python is technical aforeach loop, you should change your loop to awhile loopto have more control.range()it's just example it could be list.10times including erros or repeat each iteration until it doesn't throw an error?