Python - String list check

Question

I'm relatively new with Python, so I still struggle a bit with character manipulation.

I tried many variations of this piece of code:

print([for element in string if element[0] == '['])

"string" is a list of [tag] messages, which i splited considering '\n', so I'm trying to format it and merge separated elements of the same message. Right now I'm doing:

for count, element in enumerate(string):
        try:
            if element[0] != '[':
                string[count - 1] = string[count - 1] + ' ' + string[count]
                string.pop(count)
                count = count - 1

But it only works once per couple messages, so my goal is to check if all are properly merged.

My expected output is True if there is a "[" in the first character of the current element in the string list. So I can put it on a while loop:

while([for element in string if element[0] == '[']):
   # do something

What does string contain? Do you want to check all elements for presence of '[' ? — shahkalpesh
– shahkalpesh, Commented Nov 22, 2021 at 6:58

alphaBetaGamma · Accepted Answer · 2021-11-22 07:00:07Z

1

You are returning a list with the comprehension list. Maybe this will work better for your case

def verify(s)
    for element in s:
        if element[0] == '[':
            return True
    return False

while(verify(s)):
    .....

answered Nov 22, 2021 at 7:00

alphaBetaGamma

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Comments

Mark · Accepted Answer · 2021-11-22 07:16:46Z

1

A succinct way to do this is with any(). You can also use the build-in startswith() which helps the readability:

strings = ['hello', '[whoops]', 'test']
any(s.startswith('[') for s in strings)
# True

strings = ['hello', 'okay', 'test']
any(s.startswith('[') for s in strings)
# False

answered Nov 22, 2021 at 7:16

Mark

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1 Comment

rookie Over a year ago

Hohoo, that is pretty useful too, it's exactly the way I was trying to do with the right changes. In my code example I could do "any(element[0] == '[' for element in strings)". Thank you for your contribution Mark, appreciate it. Really learnt something new today.

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