Pythonic way to generate array with one fixed and one random column

Question

My task is to

Form array X of dimension 1000x2 by setting first column equal to 1 and drawing 1000 independent random numbers to second column from standard normal distribution.

My solution would be

import numpy as np
X1 = np.ones(1000)
X2 = np.random.randn(1000)
X = np.vstack([X1,X2]).transpose()

Now I'd like to know if there's a more elegant way to achieve the task. Maybe even a one liner?

AKX · Accepted Answer · 2021-11-15 17:17:05Z

1

Doesn't simply

np.stack([np.ones(1000), np.random.randn(1000)])

do what you want?

answered Nov 15, 2021 at 17:17

AKX

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Comments

Tom McLean · Accepted Answer · 2021-11-15 17:16:47Z

0

Here is a one-liner:

X = np.vstack([np.ones(1000),np.random.randn(1000)]).transpose()

One-liners are not necessarily better

answered Nov 15, 2021 at 17:16

Tom McLean

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7 Comments

XDAF Over a year ago

So, you suggest using my solution, i.e. three lines?

Tom McLean Over a year ago

If it makes it more readable, sure

Tom McLean Over a year ago

You could use better variable names, e.g. replace X1 with constant and X2 with random_normal

pao Over a year ago

Why do you use transpose()?

pao Over a year ago

ok thank you, I just wanted to know why transpose is used. @XDAF

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