Comparing list and int in python

Question

I'm trying to run the following piece of code:

TN = np.sum((1 - predict) * (1 - actual))

where I have predicted, the variable that I cannot modify, which gets printed as follow:

[False False False False False False]

without any comma, so I guess it is not a list. Then, I have actual which is formatted as:

[False, False, False, False, False, False]

They have the same length, but when I run the command above I get the error:

TypeError: unsupported operand type(s) for -: 'int' and 'list'

How can I convert the variable actual so it can be compared to predicted?

How predicted is generated? can you know its type using type()? — ezzeddin
– ezzeddin, Commented Nov 15, 2021 at 7:40
This is a numpy operation and predicted seems to be a numpy array so if you convert actual to a numpy array you can do the operation: TN = np.sum((1 - predict) * (1 - np.array(actual))) — user2285236
– user2285236, Commented Nov 15, 2021 at 7:41

Corralien · Accepted Answer · 2021-11-15 07:40:53Z

2

[False False False False False False] is a numpy array:

l = [False, False, False, False, False, False]

a = np.array(l)
print(a)

# Output
[False False False False False False]

I think you have to convert actual to numpy array.

answered Nov 15, 2021 at 7:40

Corralien

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