get attribute value of different nodes from xml using linq

Question

I have a xml file with data as follows

   <P1 type="CP" name="E01+W">
    <DNo>4423</DNo>
    <CNo>abc</CNo>
  </P1>

    <P2 type="DP" name="E02+W">
    <DNo>5623</DNo>
    <CNo>xyz</CNo>
  </P2>

How to I get Attribute value type="CP" and "DP" of P1 and P2 node in one column. More like Traverse to each node of and its sub node and get each subnode type attribute value in one column.

Type   Name
CP     EO1
DP     EO2

Peyman · Accepted Answer · 2011-08-08 04:46:13Z

1

You can use XDocument

var xml = XDocument.Parse([string]);
xml.Elements().Select( x => new { Type = x.Attribute("type").Value, 
                                  Name =  .Attribute("Name").Value});

edited Aug 8, 2011 at 4:46

answered Aug 8, 2011 at 4:27

Peyman

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