How to remove other values in a object key array if particular value exist?

Question

I am working on an angular project and I have an object like this

const obj = {
  fruits: ['apple', 'orange', 'None'],
  nation: ['usa'],
  city: ['New York', 'Delhi', 'None'],
  name: ['one', 'two'],
}

if the object key values have a 'None' value I have to remove the other values and keep it 'None' value only.

The answer looks like below:

const obj = {
  fruits: ['None'],
  nation: ['usa'],
  city: ['None'],
  name: ['one', 'two'],
}

Thanks in advance

akuiper · Accepted Answer · 2021-10-12 06:31:36Z

1

Loop through object, if value includes None, replace the value to the key with ['None'].

Object.entries(obj).forEach(([k, v]) => {
  if (v.includes('None')) obj[k] = ['None']
})

const obj = {
  fruits: ['apple', 'orange', 'None'],
  nation: ['usa'],
  city: ['New York', 'Delhi', 'None'],
  name: ['one', 'two'],
}
  
Object.entries(obj).forEach(([k, v]) => {
  if (v.includes('None')) obj[k] = ['None']
})

console.log(obj)

For typescript playground.

edited Oct 12, 2021 at 6:31

answered Oct 12, 2021 at 5:48

akuiper

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4 Comments

imjayabal Over a year ago

angular6 typescript throwing error 'error TS2339: Property 'includes' does not exist on type '{}'

akuiper Over a year ago

Does your obj value always has array type ?

imjayabal Over a year ago

Yes. I have to send the payload above format only. obj value always has array type

akuiper Over a year ago

The error indicates the value could be {}. It works at this playground.

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