regex for not matching alpha plus numeric range

Question

I have the following regex

.{19}_.{3}PDR_.{8}(ABCD|CTNE|PFRE)006[0-9][0-9].{3}_.{6}\.POC

a match is for example

NRM_0157F0680884976_598PDR_T0060000ABCD00619_00_6I1N0T.POC

and would like to negate the (ABCD|CTNE|PFRE)006[0-9][0-9] portion such that

NRM_0157F0680884976_598PDR_T0060000ABCD00719_00_6I1N0T.POC

is a match but

NRM_0157F0680884976_598PDR_T0060000ABCD007192_00_6I1N0T.POC

or

NRM_0157F0680884976_598PDR_T0060000ABCD0061_00_6I1N0T.POC

is not (the negated part must be 9 chars long just like the non negated part for a total length of 58 chars).

Why it seems dont work? The first expression seems to work and it is possible just to negate it for case 2: !str.matches(".*(ABCD006[0-9][0-9]|CTNE006[0-9][0-9]|PFRE006[0-9][0-9]).*"), or negate the entire pattern using matches(). Ideone online demo — Nowhere Man
– Nowhere Man, Commented Oct 6, 2021 at 6:38

Tim Biegeleisen · Accepted Answer · 2021-10-06 05:26:24Z

4

Consider using the following pattern:

\b(?:ABCD|CTNE|PFRE)006[0-9][0-9]\b

Sample Java code:

String input = "Matching value is ABCD00601 but EFG123 is non matching";
Pattern r = Pattern.compile("\\b(?:ABCD|CTNE|PFRE)006[0-9][0-9]\\b");
Matcher m = r.matcher(input);
while (m.find()) {
    System.out.println("Found a match: " + m.group());
}

This prints:

Found a match: ABCD00601

answered Oct 6, 2021 at 5:26

Tim Biegeleisen

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2 Comments

user2175783 Over a year ago

This doesnt seem to work. Here it is my full regex .{19}_.{3}PDR_.{8}\b(?:ABCD|CTNE|PFRE)006[0-9][0-9]\b.{3}_.{6}\.POC. The following string fails but should be a match NRM_0157F0680884976_598PDR_T0060000ABCD00719_00_6I1N0T.POC

Tim Biegeleisen Over a year ago

Here it is my full regex ... where does my answer ever suggest this regex?

Rakshith B S · Accepted Answer · 2021-10-14 20:17:24Z

3

I would like to propose this expression ~~(ABCD|CTNE|PFRE)006\d{1,2}~~

where \d{1,2} catches any one or two digit number that is it would get any alphanumeric values from ABCD0060~ABCD00699 or CTNE0060~CTNE00699 or PFRE0060~PFRE00699

Edit #1:

as user @Hao Wu mentioned the above regex would also accept if its ABCD0060 which is not ideal so this should do the job by removing 1 from the { } we can get

alphanumeric values from ABCD00600~ABCD00699 or CTNE00600~CTNE00699 or PFRE00600~PFRE00699 so the resulting regex would be

(ABCD|CTNE|PFRE)006\d{2}

edited Oct 14, 2021 at 20:17

answered Oct 6, 2021 at 5:46

Rakshith B S

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2 Comments

Hao Wu Over a year ago

But it makes a false positive ABCD0060?

Rakshith B S Over a year ago

In the previous regex \d{1,2} would get any digit from 0-99 so I made changes to it such that \d{2} would now get any digit from 00-99,hope this fixes the issue for ABCD0060

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regex for not matching alpha plus numeric range

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(ABCD|CTNE|PFRE)006\d{2}

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(ABCD|CTNE|PFRE)006\d{2}

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