Remove assoc array from query string

Question

I like to remove an array variable conditions from a query string which will be window.location.search.

First output Before is the initial string.
Second is after removing sub
Third still contains conditions.

How can I get rid of it?

edit The unencoded string is

conditions[0][0][field]=firstname&conditions[0][0][operator]=is&conditions[0][0][value]=John&conditions[1][0][field]=lastname&conditions[1][0][operator]=is&conditions[1][0][value]=Doe

which is needed for the application.

var string = '?page=foo&sub=bar&conditions%5B0%5D%5B0%5D%5Bfield%5D=firstname&conditions%5B0%5D%5B0%5D%5Boperator%5D=is&conditions%5B0%5D%5B0%5D%5Bvalue%5D=John&conditions%5B1%5D%5B0%5D%5Bfield%5D=lastname&conditions%5B1%5D%5B0%5D%5Boperator%5D=is&conditions%5B1%5D%5B0%5D%5Bvalue%5D=Doe';
var params = new URLSearchParams(string);

console.log('Before', params.toString());

params.delete('sub');

console.log('remove sub works', params.toString());

params.delete('conditions');

console.log('conditions still exist', params.toString());

You don't have a parameter named conditions in your URL - not from the JS perspective. What you have, is parameters named conditions[0][0][field], conditions[0][0][operator], etc. — C3roe
– C3roe, Commented Sep 7, 2021 at 12:23
It's only an array from say, for example, PHP's perspective, when it parse this kind of query string. But to JS, these are all just differently named parameters. Guess you could do something like loop over all entries, and then check if the key starts with conditions - developer.mozilla.org/en-US/docs/Web/API/URLSearchParams/… — C3roe
– C3roe, Commented Sep 7, 2021 at 12:28

ikhvjs · Accepted Answer · 2021-09-07 12:36:36Z

1

Do you want this?

var string =
  "?page=foo&sub=bar&conditions%5B0%5D%5B0%5D%5Bfield%5D=firstname&conditions%5B0%5D%5B0%5D%5Boperator%5D=is&conditions%5B0%5D%5B0%5D%5Bvalue%5D=John&conditions%5B1%5D%5B0%5D%5Bfield%5D=lastname&conditions%5B1%5D%5B0%5D%5Boperator%5D=is&conditions%5B1%5D%5B0%5D%5Bvalue%5D=Doe";
const urlSearchParams = new URLSearchParams(string);

const params = Object.fromEntries(urlSearchParams.entries());

console.log({ params });

function getFilteredParams(params, filteredString) {
  let obj = {};
  for (const key in params) {
    if (key.indexOf(filteredString) == -1) {
      obj[key] = params[key];
    }
  }
  return obj;
}

console.log(getFilteredParams(params, "conditions"));

edited Sep 7, 2021 at 12:36

answered Sep 7, 2021 at 12:29

ikhvjs

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2 Comments

Xaver Over a year ago

page and sub are subject to change/missing/unknown. I really like to just to get rid of the conditions

Xaver Over a year ago

Thanks for the code, this brings me in the right direction.

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