TypeError: 'int' object is not callable error in python

Question

I am new to python, and have been doing a beginner's course on it.

I came across this piece of code during one of the lecture:

import datetime 
DOB=input("Enter the DOB:")
CurrentYear=datetime.datetime.now().year() 
CurrentAge=CurrentYear-int(DOB)
if(CurrentAge>=18):
    print("Your Age is {} and you are Adult".format(CurrentAge))
if(CurrentAge<18):
    print("Your Age is {} and you are not Adult".format(CurrentAge))
print("Condition has been verfied successfully")

This course that I am doing is from ~2018, and the instructor didn't have any error while compiling this code.

Yes, but i am still confused where exactly in this code is int being assinged twice — lonewolf303
– lonewolf303, Commented Aug 16, 2021 at 14:02
datetime.datetime.now().year is an int but you do datetime.datetime.now().year() - so you try to treat this int as a function — balderman
– balderman, Commented Aug 16, 2021 at 14:04
@SuneeshJacob 1998 , 2000, 2005. trying all ranging from the 90's — lonewolf303
– lonewolf303, Commented Aug 16, 2021 at 14:05

Suneesh Jacob · Accepted Answer · 2021-08-16 14:11:40Z

3

The issue is that the attribute year of datetime.datetime.now() is not a function, and so, it doesn't support year(). That's why it says that it is not callable. datetime.datetime.now().year is in int format, and since it is not a function, it is not callable (like this:.()).

Change CurrentYear=datetime.datetime.now().year() to CurrentYear=datetime.datetime.now().year.

The new code would be like this:

import datetime 
DOB=input("Enter the DOB:")
CurrentYear=datetime.datetime.now().year
CurrentAge=CurrentYear-int(DOB)
if(CurrentAge>=18):
    print("Your Age is {} and you are Adult".format(CurrentAge))
if(CurrentAge<18):
    print("Your Age is {} and you are not Adult".format(CurrentAge))
print("Condition has been verfied successfully")

edited Aug 16, 2021 at 14:11

answered Aug 16, 2021 at 14:03

Suneesh Jacob

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4 Comments

lonewolf303 Over a year ago

Thank you. I finally got the output.

lonewolf303 Over a year ago

can you explain what was the issue with the previous code?

Suneesh Jacob Over a year ago

The issue with the previous code is that the attribute year of datetime.datetime.now() is not a function, and so, it doesn't support year(). That's why it says that it is not callable. datetime.datetime.now().year is in int format, and since it is not a function, it is not callable (like this:.()). I will add this info in the answer.

Rishab Mamgai Over a year ago

"year" is an attribute of datetime class not a function. Hence, not callable. To access the attributes you don't have to use "()"

Sam · Accepted Answer · 2021-08-16 14:08:02Z

2

The issue is data types (hence TypeError). A data type may be a string, integer, or even a function (a function is something that is called, such as print(): notice the brackets).

You cannot put the brackets after an integer. That suggests you are trying to run it as a function.

The variable: datetime.datetime.now().year is an integer. You cannot run a function from an integer.

The correction would be from datetime.datetime.now().year() → datetime.datetime.now().year

The final code looks like this:

import datetime 
DOB=input("Enter the DOB:")
CurrentYear=datetime.datetime.now().year 
CurrentAge=CurrentYear-int(DOB)
if(CurrentAge>=18):
    print("Your Age is {} and you are Adult".format(CurrentAge))
if(CurrentAge<18):
    print("Your Age is {} and you are not Adult".format(CurrentAge))
print("Condition has been verfied successfully")

I have tested this thoroughly. Good luck with the rest of your Python course.

answered Aug 16, 2021 at 14:08

Sam

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2 Comments

lonewolf303 Over a year ago

thank you for the explanation. i wasn't able to notice it while coding simultaneously during the course and thus ended up creating a function.

Sam Over a year ago

You are very welcome, @lonewolf303. Data types can be confusing to start with. Geed luck with your Python journey! 👋

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