0

I make a table in a form to enable user to submit several item in one time. I am able to use jquery to get the first row of the value input by user. But when they type in the value in the second row, it show error. I am pretty sure there is something wrong with the array that I am using. I have try 2 methods, both method work but it only takes the value from first row only.

<form>
<table>
<thead>
<tr>
 <th>Item Code</th>
 <th>Item Name</th>
 <th>Status</th>
</tr>
</thead>
<tbody id="entrybody">
<tr>
 <td><input type="text" name="prd_code"></td>
 <td><input type="text" name="prd_name"></td>
 <td><input type="text" name="prd_cond"></td>
</tr>
<tr>
 <td><input type="text" name="prd_code"></td>
 <td><input type="text" name="prd_name"></td>
 <td><input type="text" name="prd_cond"></td>
</tr>
<tr>
 <td><input type="text" name="prd_code"></td>
 <td><input type="text" name="prd_name"></td>
 <td><input type="text" name="prd_cond"></td>
</tr>
</tbody>

</table>
</form>
$(function() {
    $.post("action.php", function(data) {
        $("[name='title']").val(data.title);
        $("[name='body']").val(data.body);
    }, "json");
    setInterval(function() {
        var itemlist = new Array;
        var count = 1;

        var title = $("[name='title']").val();
        var body = $("[name='body']").val();

        itemlist[count - 1] = {};

        $("#productbody tbody tr").each(function() {
            var that = $(this);
            if (that.find("[name='prd_code']").val().length !== 0) {
                /*itemlist.push(code);
                itemlist.push(name);
                itemlist.push(cond);*/ //method 1

                itemlist[count - 1].code = that.find("[name='prd_code']").val();
                itemlist[count - 1].name = that.find("[name='prd_name']").val();
                itemlist[count - 1].cond = that.find("[name='prd_cond']").val(); //method 2

                count++;
            }
        });

        console.log(itemlist);

    }, 2000);
});
===== Console message (first row) =====
0:
code: "test_code1"
cond: "test_status1"
name: "test_name1"
1
  • You table has no ID but in your code you call productbody Commented Aug 2, 2021 at 8:27

2 Answers 2

1

I've changed the method of the event to a .change() for this example.

Then I've changed the following code:

var itemlist = new Array;

var title = $("[name='title']").val();
var body = $("[name='body']").val();
$("#productbody  tbody tr").each(function(i) {
  var that = $(this);
  if (that.find("[name='prd_code']").val().length !== 0) {
    itemlist[i] = {};
    itemlist[i].code = that.find("[name='prd_code']").val();
    itemlist[i].name = that.find("[name='prd_name']").val();
    itemlist[i].cond = that.find("[name='prd_cond']").val(); //method 2
  }
});

One problem was that you use this itemlist[count - 1] = {}; before your foreach statement. so you only created the first object.

Demo

$(function() {
  $("#productbody  tbody tr input").change(function() {
    //setInterval(function() {
    var itemlist = new Array;

    var title = $("[name='title']").val();
    var body = $("[name='body']").val();
    $("#productbody  tbody tr").each(function(i) {
      var that = $(this);
      if (that.find("[name='prd_code']").val().length !== 0) {
        itemlist[i] = {};
        itemlist[i].code = that.find("[name='prd_code']").val();
        itemlist[i].name = that.find("[name='prd_name']").val();
        itemlist[i].cond = that.find("[name='prd_cond']").val(); //method 2
      }
    });

    console.log(itemlist);
  });
  //}, 2000);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form>
  <table id="productbody">
    <thead>
      <tr>
        <th>Item Code</th>
        <th>Item Name</th>
        <th>Status</th>
      </tr>
    </thead>
    <tbody id="entrybody">
      <tr>
        <td><input type="text" name="prd_code"></td>
        <td><input type="text" name="prd_name"></td>
        <td><input type="text" name="prd_cond"></td>
      </tr>
      <tr>
        <td><input type="text" name="prd_code"></td>
        <td><input type="text" name="prd_name"></td>
        <td><input type="text" name="prd_cond"></td>
      </tr>
      <tr>
        <td><input type="text" name="prd_code"></td>
        <td><input type="text" name="prd_name"></td>
        <td><input type="text" name="prd_cond"></td>
      </tr>
    </tbody>

  </table>
</form>

Sign up to request clarification or add additional context in comments.

Comments

0

As far as I understand you want to create an array of the values from all table cells in all rows. Here is a relative simple way to do this without JQuery.

document.addEventListener(`change`, handle);

function handle(evt) {
  if (evt.target.name.startsWith(`prd_`)) {
    // retrieve all rows
    const values = [...document.querySelectorAll(`tbody tr`)]
      // map to objects containing row number and values
      .map(row => ({
         row: row.rowIndex,
         values: [...row.querySelectorAll(`[name^='prd_']`)]
            .reduce( (acc, val) => ({...acc, [val.name]: val.value}), {})
        }))
      .filter(val => (val.values.prd_code || ``).trim().length > 0);
      
    document.querySelector(`pre`).textContent = JSON.stringify(values, null, 2);
  }
}
<table>
  <thead>
    <tr>
      <th>Item Code</th>
      <th>Item Name</th>
      <th>Status</th>
    </tr>
  </thead>
  <tbody>
    <tr>
      <td><input type="text" name="prd_code"></td>
      <td><input type="text" name="prd_name"></td>
      <td><input type="text" name="prd_cond"></td>
    </tr>
    <tr>
      <td><input type="text" name="prd_code"></td>
      <td><input type="text" name="prd_name"></td>
      <td><input type="text" name="prd_cond"></td>
    </tr>
    <tr>
      <td><input type="text" name="prd_code"></td>
      <td><input type="text" name="prd_name"></td>
      <td><input type="text" name="prd_cond"></td>
    </tr>
  </tbody>
</table>

<pre></pre>

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.