How to find index of array in a for loop

Question

I am trying to find the index of a number that is greater than 10 but the next value is less than 10:

py =    np.array([    9.7,   10.1,   10.5,  10.2,  10.1,  9.9,   9.8])

So the answer should be 4. However, the output I got was 0. How do I fix the error?

for k in range(0,len(py)):
    if py[k]>10 and py[k+1]<10:
        position_y = np.argmax(k)
        print(position_y)

Your first number is 9.7 which is <10. So its False, for the next 4 numbers, it is greater than 10 but their successors are not, except the last one. Only `1 is the answer — user15801675
– user15801675, Commented Jul 25, 2021 at 11:00
You probably want to take a look at the docs for np.argmax. It's not clear what you expect it to do here. Really you can just print(k) — Alex
– Alex, Commented Jul 25, 2021 at 11:00
The numpy.argmax() function returns indices of the max element of the array in a particular axis. — Abhi
– Abhi, Commented Jul 25, 2021 at 11:08

Abhi · Accepted Answer · 2021-07-25 11:04:44Z

2

import numpy as np
py = np.array([    9.7,   10.1,   10.5,  10.2,  10.1,  9.9,   9.8])

for index, value in enumerate(py):
    if value > 10 and py[index + 1] < 10:
        print(index)

answered Jul 25, 2021 at 11:04

Abhi

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Shreya Srivastava · Accepted Answer · 2021-07-25 11:47:26Z

1

for i in range(len(py)):
if (py[i]>10 and py[i+1]<10):
    print(i)

answered Jul 25, 2021 at 11:47

Shreya Srivastava

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