Evaluating RegEx patterns within a string

Question

I have the following code:

userInput = "develop-feature-21"
entry = "develop-feature-**"
entry = entry.replace("**", ".*");
println (userInput ==~ "$entry") // ------> false

I basically want to replace ** and add in a valid regular express .* to find all entries of develop-feature, but the problem I am having is evaluating a RegEx expression within a string.

$entry becomes develop-feature-.*, but how do I tell groovy to then evalulate .*?

You must have came to groovy from perl

OldManSeph
– OldManSeph

2021-07-19 18:12:20 +00:00
Commented Jul 19, 2021 at 18:12 — OldManSeph
– OldManSeph, Commented Jul 19, 2021 at 18:12

daggett · Accepted Answer · 2021-07-19 18:15:41Z

2

i've seen this in old version of groovy. i have 2.5 and your code works for me.

you could try to use

println (userInput ==~ entry)

instead of

println (userInput ==~ "$entry")

userInput = "develop-feature-21"
entry = "develop-feature-**"
entry = entry.replace("**", ".*");
println (userInput ==~ entry) //----------> true

edited Jul 19, 2021 at 18:15

answered Jul 19, 2021 at 18:10

daggett

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