ReactJS: Filtering in each objectof array

Question

I have an array like:

students:
  0: 
     name: "name1",
     surname: "surname1",
     age: "18"
  1: 
     name: "name2",
     surname: "surname2",
     age: "28"
  2: 
     name: "name3",
     surname: "surname3",
     age: "38"
  // and others...

And i'm trying to make a filter with a input to search in this array of Objects.

I would to filter every field in the array of object, so for example if I write in my input 38, it should return name3, surname3, 38.

The same result i would to obtain if i search name3.

Now I have implemented the filter in this way:

students.filter(student=> student.name.toLowerCase().includes(searchTerm.toLowerCase()) || student.surname.toLowerCase().includes(searchTerm.toLowerCase()) || student.age.toLowerCase().includes(searchTerm.toLowerCase()).

My question is:

How can I do to avoid having to specify the various fields in which to search in an OR?

Thank you

Lueton · Accepted Answer · 2021-06-29 15:17:39Z

2

You could do something like this:

students.filter(student => Object.values(student).some(v => v.toLowerCase().includes(searchTerm.toLowerCase())))

answered Jun 29, 2021 at 15:17

Lueton

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2 Comments

Neal Burns Over a year ago

Object.entries() is an alternate choice if you want the keys as well.

Keyz23 Over a year ago

Ooh thank you this could be a solution, I have only a problem with this suggestion.. I have some fields that could be null at the beginning infact if I use this method I receive error Cannot read property 'toLowerCase' of null

szilagyi.sandor · Accepted Answer · 2021-06-29 15:42:38Z

1

students.filter((student) => {
  // Destructure student to get values easier.
  const { name, surname, age } = student;

  // Creating an array with all the fields, setting them to lower with map, then find one that
  // satisfies the requirement. If none of them match then find will return undefined. The "!!" converts it to a bool.
  return !![name, surname, age]
    .map((x) => x.toLowerCase())
    .find((x) => x && x.includes(searchTerm.toLowerCase()));
});

Without comments:

students.filter((student) => {
  const { name, surname, age } = student;
  return !![name, surname, age]
    .map((x) => x.toLowerCase())
    .find((x) => x && x.includes(searchTerm.toLowerCase()));
});

edited Jun 29, 2021 at 15:42

answered Jun 29, 2021 at 15:22

szilagyi.sandor

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