Forming a cURL command using string concatenation in Python

Question

I'm trying to form a cURL using string concatenation in Python. I have a custom command and I'm not sure if I can use requests for this.

cmd='curl -u admin:'+password+' -F file=@'+package+' -F name='+package+' -F force=false -F install=true http://'+ip+':5101/crx/packmgr/service.jsp'
    
print(cmd)

Error:

curl -u admin:******** -F file=@abc_xyz.zip
 -F name=abc_xyz.zip
 -F force=false -F install=true http://8.8.8.8:5101/crx/packmgr/service.jsp
curl: no URL specified!
curl: try 'curl --help' or 'curl --manual' for more information
sh: line 1: -F: command not found
sh: line 2: -F: command not found
32512

And yes I have tried escape '' as well. Didn't work.

Any help would be greatly appreciated. TIA

Do have line endings in your password variable? Try password = password.strip() before construncting the command. Or, more likely in package variable? — crayxt
– crayxt, Commented Jun 10, 2021 at 15:23

crayxt · Accepted Answer · 2021-06-10 15:28:27Z

1

Looks like your constructed command has line endings after the package variable, try stripping it from extra symbols:

package = package.strip()

answered Jun 10, 2021 at 15:28

crayxt

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