javaScript - How to assign multiple dynamic values to a variables into the loop

Question

I have dynamic array of matches as:

[
      "Rivers United - Kano Pillars",
      "MFM FC - Abia Warriors",
      "Lobi Stars - Enugu Rangers",
      "Sunshine Stars - Dakkada",
      "Ifeanyi Ubah - Kwara United",
      "Enyimba - Adamawa United",
      "Empoli - Torino U19",
      "Bologna U19 - Ascoli",
      "Lazio - Inter U19",
      "Juventus U19 - Spal",
      "Milan - Fiorentina U19",
      "Sassuolo U19 - AS Roma U19",
      "Genclerbirligi - Denizlispor",
      "Goztepe - Fenerbahce",
      "Kayserispor - Demir Grup Sivasspor",
      "Trabzonspor U19 - Istanbul Basaksehir AS",
      "Fatih Karagumruk - KASIMPASA AS",
      "Portugal - Israel",
      "Wydad AC Casablanca - DHJ ",
      "Rsb Berkane - Athletic Youssoufia"
    ]

When I perform API call using supertest library based on above array, I am able to fetch single opponent and keep into a single variables and my code is:

const response = await api.getRequestAsync("https://sports/api/feeds/prematch/mostpopularsports/en/1/5/6/", `2021-06-06`, "", "");
        const otp = api.jsonPath(response.body, `$[0].AreaMatches[0].Items..ItemName`);
        let opponent1 = otp[0].split(" - ")[0];
        let opponent2 = otp[0].split(" - ")[1];

        let opponent20 = otp[5].split(" - ")[1];
        console.log(opponent1 + " | " + opponent2 + " | " + opponent20);

which produces variables as: opponent1, opponent2...opponent20

and console output as: [0-0] Rivers United | Kano Pillars | Adamawa United

But this creates manual work to assign value to every single variable.

How can I transfer this code to loop logic, so dynamically will have variable for every single opponent: Rivers United, Kano Pillars...Athletic Youssoufia

and variables as: opponent1, opponent2...opponent20

Peter Pointer · Accepted Answer · 2021-06-09 13:45:49Z

2

Well you can use arrays to store multiple values for example, as you are already using. You just have to create these variables yourself.

See JavaScript - Array from Mozilla Web Docs

In your example code you access otp which has the opponents as strings. We can create a loop over otp to fill arrays with the result of your split() call.

Here is a simple example code you can adapt to your liking:

let opponentsLeft = [];
let opponentsRight = [];

for(var i=0; i < otp.length; i++) {
  var split = otp[i].split(" - ");
  
  opponentsLeft.push(split[0]);
  opponentsRight.push(split[1]);
}

In more modern JavaScript you can use forEach():

let opponentsLeft = [];
let opponentsRight = [];

otp.forEach(element => {
  var split = element.split(" - ");
  
  opponentsLeft.push(split[0]);
  opponentsRight.push(split[1]);
});

You can do what you want with the resulting arrays. Again, just modify to your liking.

You can then write a loop over those arrays to do what you wish:

for(var o = 0; o < opponentsLeft.length; o++) {
  console.log('left', opponentsLeft[o]);
  console.log('right', opponentsRight[o]);
}

edited Jun 9, 2021 at 13:45

answered Jun 9, 2021 at 13:03

Peter Pointer

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4 Comments

vlatko606 Over a year ago

thanks for the answer. But this is only transferring from a single array to 2 separated arrays. After transferring, how can create variables? thanks

Peter Pointer Over a year ago

Why would you want to create the variables? That was your problem in the first place, wasn't it? Of course you can just create another for loop for the created arrays.

vlatko606 Over a year ago

well the most important is the creation of those dynamic variables, opponent1, opponent2...opponent20. I need those for further operations

Peter Pointer Over a year ago

You cannot in JavaScript. Just use a for() loop.. I'll update the answer.

vlatko606 · Accepted Answer · 2021-06-09 13:58:58Z

0

Hey @Peter Krebs thanks for your efforts, but the solution that i need is:

        let opponentsA = [];
        let opponentsB = [];

        for (var i = 0; i < otp.length; i++) {
            opponentsA[i] = otp[i].split(" - ")[0];
            opponentsB[i] = otp[i].split(" - ")[1];

        }

        console.log(opponentsA[0]); //access the 1st opponent dynamically
        console.log(opponentsA[20]); //access the 20h opponent dynamically

answered Jun 9, 2021 at 13:58

vlatko606

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