How to convert this in Java using List or Hashmap?
{"mappingSet": ["key1": "value1", "key2": "value2"]}
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Is the question here how to parse json into list or hashmap without any dependencies?deepakchethan– deepakchethan2021-06-09 03:53:44 +00:00Commented Jun 9, 2021 at 3:53
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2That isn't legal JSON, so I think you're going to have difficulties finding anything that would work. That array needs to be an object. If you really need to parse malformed JSON, you're going to have to do it by hand.Gabe Sechan– Gabe Sechan2021-06-09 05:48:05 +00:00Commented Jun 9, 2021 at 5:48
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@Rohini The JSON is invalid.Most Noble Rabbit– Most Noble Rabbit2021-06-09 06:08:20 +00:00Commented Jun 9, 2021 at 6:08
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1 Answer
you could use some third party lib like
- gson
- jackson
then you can covert json string to
- pre-defined objects
- lib built in objects like JsonObject(JsonArray, JsonElement) in 1.gson and JsonNode in 2.jackson
example here
ObjectMapper objectMapper = new ObjectMapper();
String jsonArray = "[{ \"color\" : \"Black\", \"type\" : \"FIAT\" }, { \"color\" : \"Green\", \"type\" : \"NIKE\" }]";
JsonNode jsonNodeArray = objectMapper.readTree(jsonArray);
System.out.println(jsonNodeArray);
System.out.println(jsonNodeArray.get(0));
6 Comments
Rohini
inside the json array there is no json object.
Wess Wang
by the way, I don't think your json string above is valid in format. json array could not contain key value pair
Rohini
its a valid json.
Gabe Sechan
@Rohini No, it isn't. You can't have key:value fields in an array. Run it past a JSON validator like JSONlint- it fails.
Wess Wang
you can copy paste to any online json parser
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