Javascript array filter out numbers represented as strings

Question

I have an array like this:

a = ["name","text","dog","1","2","cat"]

I want to filter out all the numbers represented as strings (integers and floats) from the above given array. In this case I want to filter out "1", "2"

Desired Output

a=["name","text","dog","cat"]

Note: I am looking for a clean and elegant way to solve this. A naive approach that comes to my mind is to try and typecast to a float (which would cover both integers and floats) and if it fails, only then I should include the element in the array. I was wondering if there is a better way to solve this.

Majed Badawi · Accepted Answer · 2021-06-06 12:57:36Z

3

You can iterate over the array using Array#filter and only keep the elements that are not numbers using isNaN:

const a = ["name","text","dog","1","2","cat",".2"];

const res = a.filter(isNaN);

console.log(res);

edited Jun 6, 2021 at 12:57

answered Jun 6, 2021 at 12:51

Majed Badawi

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6 Comments

dracarys Over a year ago

Great, this works! Can you explain a little as to why?

dracarys Over a year ago

My use case was for numbers and that is what I intended, sorry for the confusion. I can edit the Question to make that clearer

Reinis Over a year ago

isNaN('2005/12/12') //true what do you think? you says?

Reinis Over a year ago

Number.isInteger('2005/12/12'); //false, what do you mean integer?

Majed Badawi Over a year ago

@SeniorWebEngineer this value is not a number, neither an integer. Can you clarify your question?

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