how to assign output of command to another variable in shell [duplicate]

Question

how do i assign the output of command to another variable in shell, here what i tried.

summary = `grep -A 4 '#HM based Segregation FEP (WNS)(TNS)' some_file | awk '{print $2, $3}' | sed 's/,=,//g' | tr '\n' ',' | sed 's/based Segregation,//g' | sed 's/(\|\ (/\//g' | sed 's/)//g'`

summary1 = $(grep -A 4 '#HM based Segregation FEP (WNS)(TNS)' some_file | awk '{print $2, $3}' | sed 's/,=,//g' | tr '\n' ',' | sed 's/based Segregation,//g' | sed 's/(\|\ (/\//g' | sed 's/)//g')
echo "$summary"
echo "$summary1"

basically, I am grepping from some patterns and removing unwanted data. and the output is

summary: Command not found.
Illegal variable name.

what am I doing wrong?

A variable may be assigned to by a statement of the form name=[value], with no space before and after the equal sign. gnu.org/software/bash/manual/html_node/… — Philippe
– Philippe, Commented May 2, 2021 at 8:00

loleary · Accepted Answer · 2021-05-03 01:12:36Z

2

Shell variable assignment syntax is var=value. Remove the spaces around the equal. For example:

summary="$(grep -A 4 '#HM based Segregation FEP (WNS)(TNS)' some_file | awk '{print $2, $3}' | sed 's/,=,//g' | tr '\n' ',' | sed 's/based Segregation,//g' | sed 's/(\|\ (/\//g' | sed 's/)//g')"

answered May 3, 2021 at 1:12

loleary

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1 Comment

Charles Duffy Over a year ago

Duplicates should be closed, not answered. See the "Answer Well-Asked Questions" section of How to Answer.

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