I have tow arrays of object like this :
const array1 = [
{ id: 1, name: 'A' },
{ id: 2, name: 'B' },
{ id: 3, name: 'C' }
]
const array2 = [
{ id: 1, name: 'A' },
{ id: 2, name: 'B' }
]
I want another array from arry1 which contains those objects which are not in array2. like this :
[{ id: 1, name: 'C' }]
I tried this approach : var finalArray = array1.filter(function (obj) { return array2.indexOf(obj) === -1; });
But its not working. Please help me
try this :
const array1 = [
{ id: 1, name: 'A' },
{ id: 2, name: 'B' },
{ id: 3, name: 'C' }
]
const array2 = [
{ id: 1, name: 'A' },
{ id: 2, name: 'B' }
]
const array2Names = array2.map(e => e.name)
const arrayYouWant = array1.filter(e => array2Names.includes(e.name) === false)
The array2Names variable return an array like this : ['A','B']
The includes method allows us to know if the analyzed array contains the element in parentheses.
We can use Array.filter and Array.find to get all the objects in array1, but not in array2.
We use .filter to find all the items in array1 that are not present in array2, using .find.
const array1 = [
{ id: 1, name: 'A' },
{ id: 2, name: 'B' },
{ id: 3, name: 'C' }
]
const array2 = [
{ id: 1, name: 'A' },
{ id: 2, name: 'B' }
]
const diff = array1.filter(x1 => !array2.find(x2 => {
return x1.id === x2.id && x1.name === x2.name;
}));
console.log(diff);
const array1 = [
{ id: 1, name: 'A' },
{ id: 2, name: 'B' },
{ id: 3, name: 'C' }
]
const array2 = [
{ id: 1, name: 'A' },
{ id: 2, name: 'B' }
]
const arr = [... new Set(array1.filter(el => !array2.some(el2 => el2.id == el.id)))];
console.log(arr);
