I have a list called quan = [0, 0 ,0, 0]. I'm asking the user to input integers between 0 to 3 and storing them in another list called items. eg: items = [0, 1, 1, 2, 2, 2].
For each int in items, I want to increment the corresponding position in quan, i.e., quan should become [1, 2, 3, 0] in this case.
for i in items:
quan[items[i]] += 1
so far all I've ended up with an EoL error. A nudge in the right direction would be appreciated. Thanks.
For the question as asked:
quan = [0, 0, 0, 0]
items = [0, 1, 1, 2, 2, 2]
for i in items:
quan[i] += 1
In most real situations, though, you probably want to use collections.Counter instead, which provides the same answer in slightly different form:
from collections import Counter
items = [0, 1, 1, 2, 2, 2]
quan = Counter(items)
Counter does something entirely different. (Not to mention that quan is probably not always all zero at the start.)The correct code is:
for i in items:
quan[i]+=1
The EOL might be caused by a typo somewhere in the code.
Below code loop will iterate only 4 times rather than no. of elements in items' list. count() of the list will return no. of occurrences of that element.
quan = [0, 0, 0, 0]
items = [0, 1, 1, 2, 2, 2]
for i in range(4):
quan[i] += items.count(i)
print(quan)
or alternatively
quan = [quan[i]+items.count(i) for i in range(4)]
quan[i] += 1.icontains the element, not the index so you can access it directly usingquan[i].