How to check if values in array is present in object key of object array

You can use filter and some for that:

var objectArr = [{id: "id1"}, {id: "id3"}]
var arr1 = ["id1", "id2"];
const notFounds = arr1.filter(el => !objectArr.some(obj => obj.id === el ));
console.log(notFounds); // ["id2"]

JS Array some:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/some

JS Array filter:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

If You iterate over objectArr, You can get object fields in form of array with: Object.entries(your_object).

for (const obj of objectArr) {
    for (const item of Object.entries(obj)) {
        // where item is field in object
        // now You can compare if item is in [id1,id2]
    }
}

You can try something like this

var arr = ["id1", "id2", "id3", "id4"];
var n = arr.includes("id2"); //true

For an array of objects. If the id is unique in the array

var arr = [{id:"id1"},{id:"id2"},{id:"id3"},{id:"id4"}]
const found = arr.some(el => el.id === "id3") // true

EDIT: ran.t has a better answer that keeps track of which ids are not found.

It sounds like what you're looking for is .every() method. Which will allow you can check each element in the array passes a given condition.

You can combine this with the .some() method to check at least one object in the objectArr has id equal to your element

const allElementsFound = ["id1", "id2"].every(el => objectArr.some(obj => obj.id === el))
if(!allElementsFound) {
    // throw error 
}