Filter array of objects where one object's array has at least one match with another array

Question

I apologize in advance, couldn't come up with a better example for data.

So I have the array things, which currently just consists of objects that contain an id property and an array which just contains random things/words I could suddenly come up with, and other_things, with with some random words from things array.

let things=[
  {
    id: 1,
    names: ['car','door','chair']
  },
  {
    id: 2,
    names: ['cat','dog','door']
  },
  {
    id: 3,
    names: ['phone','mouse','cat']
  },
  {
    id: 4,
    names: ['building','desk','pen']
  },
  {
    id: 5,
    names: ['road','date','number']
  }
];

let other_things=['car','door','pen'];

What I'd like to achieve is to filter array things, and only get those objects/elements, where the names array contains at least one element from the other_things array.

In this example, only things[2] and things[4] have no matches with any words from other_things, so we don't need them.

I have already tried many things, like combining ES6 methods, like filter, every or map, tried using nested for loops, but nothing has worked out for me unfortunately.

const other = { car: true, door: true, pen: true }; /* can be generated from array */ let result = things.filter(({ names }) => names.some(e => other[e] ?? false )); If your items aren't strings, use a Map instead, or just do something cheap like includes or indexOf on ither_things directly, if you only have a couple dozen or hundred items at best. — ASDFGerte
– ASDFGerte, Commented Jan 3, 2021 at 13:52
Tbh, for the structure to check, even a Set should be enough, you don't care about insertion order or anything. — ASDFGerte
– ASDFGerte, Commented Jan 3, 2021 at 14:01

Nishant · Accepted Answer · 2021-01-03 13:58:07Z

3

let things=[
  {
    id: 1,
    names: ['car','door','chair']
  },
  {
    id: 2,
    names: ['cat','dog','door']
  },
  {
    id: 3,
    names: ['phone','mouse','cat']
  },
  {
    id: 4,
    names: ['building','desk','pen']
  },
  {
    id: 5,
    names: ['road','date','number']
  }
];

let other_things=['car','door','pen'];

console.log(things.filter(t => t.names.filter(n => other_things.includes(n)).length > 0))

answered Jan 3, 2021 at 13:58

Nishant

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