How to run a script with additional environment variable Debug=* in VSCode in Node.js?

Question

this is my code :

const CrawlE = require('crawl-e/v0.5.2')
const debug = require('debug')


let crawlE = new CrawlE({
  cinemas: [
    {
      name: 'Kino Gmunden',
      address: 'Theatergasse 7, 4810 Gmunden',
      website: 'http://www.kino-gmunden.at/',
      phone: '0676 / 88 794 505'
    }
  ],

  showtimes: {
    url: 'https://www.daskino.at/programm/',
  }
  
})

crawlE.crawl()

i want to add an environment variable Debug=*, how can i set it and make this script run with it ?

Ivan V. · Accepted Answer · 2020-12-26 13:29:11Z

2

If you are running your script from the command line just set the environment variable before running the script

// command line
DEBUG=* node index.js

// package.json
"scripts": {
  "test": "DEBUG=* node index.js"
},

// example vscode launch configuration
{
  "type": "node",
  "request": "launch",
  "env": { "DEBUG": "*" }, // -> this is the important part!
  "name": "Main",
  "program": "${workspaceFolder}/src/index.js",
  "skipFiles": [
    "${workspaceFolder}/node_modules/**/*.js",
    "<node_internals>/**/*.js"
  ]
},

edited Dec 26, 2020 at 13:29

answered Dec 25, 2020 at 22:58

Ivan V.

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3 Comments

mikmir7 Over a year ago

I am running it from the option in VS CODE!

mikmir7 Over a year ago

where should i set it because i am so confused?

Ivan V. Over a year ago

I've updated my answer to include package.json and vscode launch configuration.

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