Converting a multi-line text file to a python string

Question

I have a text file that has a sequence of four characters a,b,c,d which is 100 lines long that I want to convert to a text string.

There are lines in the txt file that have asterisks that I want to skip entirely.

Here is an example of how the txt file can look. Note the third row has an asterisk where I want to skip the entire row

abcddbabcbbbdccbbdbaaabcbdbab
bacbdbbccdcbdabaabbbdcbababdb
bccddb*bacddcccbabababbdbdbcb

Below is how I'm trying to do this.

s = ''
with open("letters.txt", "r") as letr:
        for line in letr:
            if '*' not in line:
                s.join(line)

Are you trying to preserve line breaks, or do you want one long string? — Mark
– Mark, Commented Dec 22, 2020 at 3:00

dudulu · Accepted Answer · 2020-12-22 03:09:14Z

2

Need to use readlines() function.

This is an example, please modify it yourself.

s = ''
with open("letters.txt", "r") as letr:
       result = letr.readlines()

print(result)

for line in result:
    if '*' not in line:
        s += line 
        print(line)

print(s)

I looked at other answers and found that I made a mistake, your code s.join(line) --> s += line is ok.

edited Dec 22, 2020 at 3:09

answered Dec 22, 2020 at 2:56

dudulu

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Comments

elonzh · Accepted Answer · 2020-12-22 03:01:34Z

1

s = ''
with open("letters.txt", "r") as letr:
        for line in letr:
            if '*' not in line:
                s += line

builtin type str.method return a string which is the concatenation of the strings in iterable. you should use s += line for contacting string one by one.

Iterate a text file is not a problem.

answered Dec 22, 2020 at 3:01

elonzh

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