Swift init empty array with the same type as another array

Question

I'm a very beginner at Swift, so this question might be silly.

I want to have a function, where an empty array is created with the same type as an incoming parameter.
I tried something like below, but none of it works.

private func doSomething<T>(source: [T]) {
    var result = [source]
    var result = [source]()
    var result = [type(of:source)]()
    var result: type(of:source) = Array()
}

I see an option to do like this:

private func shuffle<T>(source: [T]) {
    var result = source
    result = []
}

But is there a better way to achieve what I want?

Sulthan · Accepted Answer · 2020-11-28 16:52:31Z

4

simply:

var result = [T]()

or

var result: [T] = []

answered Nov 28, 2020 at 16:52

Sulthan

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Comments

Kamil.S · Accepted Answer · 2020-11-28 16:52:28Z

2

You can do this:

private func shuffle<T>(source: [T]) {
    var result: [T] = []
    //do something with your result (being an empty array at this point)
}

answered Nov 28, 2020 at 16:52

Kamil.S

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