Vs code regex replace part of string and keep other [duplicate]

Question

I need quick help with regex I have

'http://127.0.0.1:5000/register'

and want to replace it with

`${process.env.API_URL}/register`

doing this regex:

'http://127.0.0.1:5000/.*'

takes the whole thing

You don't need .*. Just replace http://127.0.0.1:5000/ with ${process.env.API_URL}/ — Barmar
– Barmar, Commented Nov 19, 2020 at 8:30

Barmar · Accepted Answer · 2020-11-19 08:33:38Z

3

Use a capture group to copy the part after /

Find: 'http://127.0.0.1:5000/(.*)'

Replace: `${process.env.API_URL}/$1`

answered Nov 19, 2020 at 8:33

Barmar

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