Discord bot in python

Question

I'm trying to make a discord bot that sends a random image of goat (which are in a folder) when a user types !goat. But I can't get there and can't really find cases like mine.

Here is my code:

import discord
import random
import os

class MyClient(discord.Client):
    async def on_ready(self):
        print('Logged in as')
        print(self.user.name)
        print(self.user.id)
        print('------')

    async def on_message(self, message):
        # we do not want the bot to reply to itself
        if message.author.id == self.user.id:
            return

        if message.content.startswith('!goat'):

            with open(random.choice(os.listdir("/home/leo/Bureau/bot-discord/image")), 'rb') as f:
                picture = discord.File(f)
                await channel.send(channel, picture)

Thanks for your answers.

listdir returns the name of the files, not the complete paths. — njzk2
– njzk2, Commented Nov 16, 2020 at 22:22
Oh ok it's a problem lol. Do you have any method I can use ? — Léo Carrez
– Léo Carrez, Commented Nov 16, 2020 at 22:24
@LéoCarrez why not just store the path in a variable, then concatenate the path and the file name? — Random Davis
– Random Davis, Commented Nov 16, 2020 at 22:40
Have a look at glob.glob. I think that is exactly what you're looking for. — Hampus Larsson
– Hampus Larsson, Commented Nov 16, 2020 at 22:45
Because my code works, he takes a random image in my folder but he don't send the picture on discord he return an error like : FileNotFoundError: [Errno 2] No such file or directory: 'the Name Of The Picture'. — Léo Carrez
– Léo Carrez, Commented Nov 16, 2020 at 22:46

Hampus Larsson · Accepted Answer · 2020-11-16 22:52:55Z

2

I think that you can solve your problem using glob.glob:

import glob
from pprint import pprint
from random import choice

goats = glob.glob("P:/Goats/*.png")
pprint(goats)
print(choice(goats), "is the chosen one!")

Output:

['P:/Goats\\Goat0.png',
 'P:/Goats\\Goat1.png',
 'P:/Goats\\Goat2.png',
 'P:/Goats\\Goat3.png',
 'P:/Goats\\Goat4.png',
 'P:/Goats\\Goat5.png',
 'P:/Goats\\Goat6.png',
 'P:/Goats\\Goat7.png',
 'P:/Goats\\Goat8.png',
 'P:/Goats\\Goat9.png']
P:/Goats\Goat2.png is the chosen one!

answered Nov 16, 2020 at 22:52

Hampus Larsson

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4 Comments

Léo Carrez Over a year ago

Thanks your code is worked but i don't know how i can send the picture on channel discord

Sachin Raja Over a year ago

Use discord.File: channel.send(file=discord.File(fp="path/to/file.png", filename="image.png")).

Hampus Larsson Over a year ago

@LéoCarrez You have to target the channel that the message was sent from. I'm not 100%, but you should be able to access the channel-object via message.channel in your original code.

Léo Carrez Over a year ago

Do you know how can I do that because i've try to found it on discord.py doc but i don't understand how it's works.

njzk2 · Accepted Answer · 2020-11-17 20:07:45Z

0

I have finally found the answer on several forum and doc. So my code is :

import discord
import glob
from pprint import pprint
from random import choice

class MyClient(discord.Client):
    async def on_ready(self):
        print('Logged in as')
        print(self.user.name)
        print(self.user.id)
        print('------')

    async def on_message(self, message):
        # we do not want the bot to reply to itself
        if message.author.id == self.user.id:
            return

        if message.content.startswith('!goat'):

            goat = glob.glob("/home/leo/Bureau/bot-discord/image/*.jpeg")
            pprint(goat)
            image = choice(goat)

            await message.channel.send(file=discord.File(image))

thanks everyone for your answers. Have a good day.

edited Nov 17, 2020 at 20:07

njzk2

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answered Nov 17, 2020 at 12:23

Léo Carrez

96 bronze badges

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