How to get and display the lowest value from an array inside an array?

Question

this is my array:

[{
            "AC": "true",
            "doj": "2020-11-20T00:00:00+05:30",
            "fareDetails": [
                {
                    "baseFare": "1033.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1085.00"
                },
                {
                    "baseFare": "1086.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1140.00"
                },
                {
                    "baseFare": "1190.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1250.00"
                },
                {
                    "baseFare": "1243.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1305.00"
                }
            ],
            "fares": [
                "1250.00",
                "1305.00",
                "1140.00",
                "1085.00"
            ],
        },..........],

I need to show the lowest "baseFare" among the given array, as there are four base fare i need show only the lowest and it should be in numbers like 1033 without decimals

So far i tried this , but it gives error

 Math.round(Math.min(...item.fareDetails.baseFare)

How to achive this ?

From an array of objects, extract value of a property as array -> then get Math.min from that. — VLAZ
– VLAZ, Commented Nov 11, 2020 at 15:49

Zulqarnain Jalil · Accepted Answer · 2020-11-11 16:20:17Z

1

you can use the combination of Math.min and yourArry.map

like this

Math.min.apply( Math, t[0].fareDetails.map(x=>x.baseFare))

var t =[{
            "AC": "true",
            "doj": "2020-11-20T00:00:00+05:30",
            "fareDetails": [
                {
                    "baseFare": "1033.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1085.00"
                },
                {
                    "baseFare": "1086.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1140.00"
                },
                {
                    "baseFare": "1190.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1250.00"
                },
                {
                    "baseFare": "1243.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1305.00"
                }
            ],
            "fares": [
                "1250.00",
                "1305.00",
                "1140.00",
                "1085.00"
            ],
        },{
            "AC": "true",
            "doj": "2020-11-20T00:00:00+05:30",
            "fareDetails": [
                {
                    "baseFare": "12.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1085.00"
                },
                {
                    "baseFare": "444.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1140.00"
                },
                {
                    "baseFare": "22.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1250.00"
                },
                {
                    "baseFare": "111.00",
                    "srtFee": "0.0",
                    "tollFee": "0.0",
                    "totalFare": "1305.00"
                }
            ],
            "fares": [
                "1250.00",
                "1305.00",
                "1140.00",
                "1085.00"
            ],
        }]
var lowest =Math.min.apply(Math,t.flatMap(x=> x.fareDetails.map(x=>x.baseFare)))
console.log(lowest)

edited Nov 11, 2020 at 16:20

answered Nov 11, 2020 at 15:55

Zulqarnain Jalil

1,69117 silver badges27 bronze badges

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5 Comments

Torbjörn Stabo Over a year ago

Why Math as the 1st arg to apply()?

VLAZ Over a year ago

.map(/* ... */ .map( /* ... */)).join().split(",")??? Why go through all the trouble for a trivial operation like flattening an array?

Zulqarnain Jalil Over a year ago

I just want to get all baseFare in a single Array to process it

VLAZ Over a year ago

@ZulqarnainJalil yes, I'm aware of that. I wonder why convert to a string and split it back into another array instead of just flatMap-ping?

Zulqarnain Jalil Over a year ago

Yes flatMap is better way to get rid of all join and split i have edited the answer

Derek Wang · Accepted Answer · 2020-11-11 15:53:40Z

0

You need to extract baseFare values from the array item and get the min value among them as follows.

Math.round(Math.min(...item.map(({ fareDetails: { baseFare } }) => Number(baseFare))));

answered Nov 11, 2020 at 15:53

Derek Wang

10.2k4 gold badges20 silver badges40 bronze badges

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