Sort 2d array in Javascriptusing both fields [duplicate]

Question

I have a simple 2D array that I want to sort with two conditions.

[ [ "the,", 3 ], [ "who,", 3 ], [ "take,", 4 ], [ "over,", 4 ], [ "world,", 5 ] ]

Sort by number ascending
Then sort alphabetically descending

Expected result would be the who word. First step is achieved with below code:

arraySorted = arrCom.sort((a, b) => a[1] - b[1] || a[0] - b[0]);

Duplicate of Sort array by firstname (alphabetically) in Javascript. — Sebastian Simon
– Sebastian Simon, Commented Oct 3, 2020 at 0:04

CertainPerformance · Accepted Answer · 2020-10-02 23:38:22Z

1

If the first comparison comes out to 0 (same number), use localeCompare to compare alphabetically:

const arr = [ [ "the,", 3 ], [ "who,", 3 ], [ "take,", 4 ], [ "over,", 4 ], [ "world,", 5 ] ];
arr.sort(
  (a, b) => a[1] - b[1] || b[0].localeCompare(a[0])
);
console.log(arr);

edited Oct 2, 2020 at 23:38

answered Oct 2, 2020 at 23:30

CertainPerformance

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3 Comments

marcin2x4 Over a year ago

Thank you but still the appears first :)

CertainPerformance Over a year ago

Do you mean you want z y x etc? Just switch around the a and b

marcin2x4 Over a year ago

Yes, alphabetical descending.

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