I have an array like so: ['A', 'B', 'C', 'D', 'E'].
I've been trying to figure out how to make it like so: ['AB', 'CD', 'E']
I'm not sure where to start. Thanks in advance!
5 Answers
main.py
a = ['A', 'B', 'C', 'D', 'E']
b = [i + j for i, j in zip(a[:-1:2], a[1::2])]
if len(a) % 2 == 1:
b.append(a[-1])
print(b)
result
$ python main.py
['AB', 'CD', 'E']
3 Comments
Wt.N
Thank you I figured it out the question. Fixed and updated.
Wt.N
Thank you for check. fixed but your answer is much better for reading and computational efficiency
superb rain
You could make yours perhaps a bit prettier with
zip(a[::2], a[1::2] + ['']), although it's less efficient.>>> [''.join(a[i:i+2]) for i in range(0, len(a), 2)]
['AB', 'CD', 'E']
or (as I love iterators)
>>> it = iter(a)
>>> [s + next(it, '') for s in it]
['AB', 'CD', 'E']
1 Comment
dylatwork
Wow, Thanks a ton! I really appreciate it
I think that the easier way is to iterate through the array and concatenate the chars, it works if you have an array with even length, so you could add a check and append the last element in case of odd length.
array = ['A', 'B', 'C', 'D', 'E']
array2 = [f"{array[i]}{array[i+1]}" for i in range(0, len(array)-1, 2)]
if len(array)%2!=0:
array2.append(array[-1])
print(array2)
Comments
Try like this. This is very bare answer but should work.
my_array = ['A', 'B', 'C', 'D', 'E']
def combine_array(my_array):
mixed_array = []
start_new = True
for item in my_array:
if start_new:
mixed_array.append(item)
start_new = False
else:
mixed_array[-1] = mixed_array[-1] + item
start_new = True
return mixed_array
if __name__ == "__main__":
try:
print(combine_array(my_array))
except Exception as err:
print(err)
2 Comments
ilyas Jumadurdyew
Can someone explain why I got minus ?! This answer is tested and its working.
superb rain
Maybe someone didn't like the amount of code. I don't like that, either, but it's correct, efficient and simple, so I countervoted.
startArray = ['A', 'B', 'C', 'D', 'E']
currentIndex = 0
finishArray = ['']
for x in startArray:
if len(finishArray[currentIndex]) == 2:
currentIndex += 1
finishArray.insert(currentIndex,x)
else:
finishArray[currentIndex] += x
print(finishArray)
for n in range(0,len(array)): newarray[n//2] += array[n]grouperrecipe from theitertoolsdocumentation provides a decent solution