Running a python script from a command line in Windows

Question

I'm currently following the book, "Learning Python The Hard Way" and I am stuck trying to make a script run from the command line.

I have saved this text:

from sys import argv

script, first, second, third = argv

print "The script is called:", script
print "Your first variable is:", first
print "Your second variable is:", second
print "Your third variable is:", third

as ex13.py in my Python folder. When I try to run it from cmd, it comes up with this error:

"File "<stdin>", line 1
python ex13.py first 2nd 3rd
          ^

Can you explain what this means and how I can fix it? Sorry for being a noob :)

andrewdski · Accepted Answer · 2011-06-19 12:48:31Z

7

It looks like you are typing the line

python ex13.py first 2nd 3rd

into the python interpreter. You are supposed to type that at the cmd prompt.

answered Jun 19, 2011 at 12:48

andrewdski

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2 Comments

James Over a year ago

I just tried that and it says this "python: can't open file 'ex13.py': [Errno 2] because there is no such file or directory."

Wooble Over a year ago

James: then you need to cd to the directory containing the script, or use the full pathname.

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