Create x amounts of lists using a for loop in python

Question

I'm trying to make 1 list for every item in this list, but the length of the list is based on user input, so that is why I'm using a for a loop.

My Idea:

listno = 0
for i in arialabel:
    a+str(listno) = []
    print(a+str(listno))
    listno+=1

My current problem is that you can't use operators in the names of variables.

yourlists = []; for _ in range(howmany): yourlists.append([]) — user5386938
– user5386938, Commented Sep 18, 2020 at 17:19
Yes you should not use that, please provide more info of what you are doing.I would suggest you to simply make a list of list for that usage. — Shahir Ansari
– Shahir Ansari, Commented Sep 18, 2020 at 17:39

CryptoFool · Accepted Answer · 2020-09-18 17:30:29Z

1

Put your lists in a dictionary:

arialabel = ['w', 'x', 'y', 'z']
prefix = "a"

lists = {}
listno = 0
for i in arialabel:
    lists[prefix+str(listno)] = []
    print(prefix+str(listno))
    listno+=1

print(lists)

Result:

a0
a1
a2
a3
{'a0': [], 'a1': [], 'a2': [], 'a3': []}

Example of usage:

lists['a3'].append("apple")
lists['a3'].append("pear")
print(lists['a3'])

Example result:

['apple', 'pear']

edited Sep 18, 2020 at 17:30

answered Sep 18, 2020 at 17:19

CryptoFool

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2 Comments

Random Davis Over a year ago

I think a+str(listno) was a variable OP was trying to define with that name, i.e. a1, a2, ... So in order to replicate what they want, you'd replace a+str(listno) with "a"+str(listno). Also you can demonstrate how to get the value from the dict which might be helpful.

CryptoFool Over a year ago

ah, ok. easy. just change prefix

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