I have a array of [2 2 3 4 4 5 6 6 6], and want to delete all minimum values from it.
The output should be [3 4 4 5 6 6 6].
I tried like following code, but it deleted a single 2, and left [2 3 4 4 5 6 6 6].
import numpy as np
a = np.array([2,2,3,4,4,5,6,6,6])
b= np.delete(a, a.argmin())
Python has a built-in function for finding min
val = min(values)
b =[v for v in values if v != val]
min() or not to a.min() depends on the array size.
b = a[a > min(a)]
[b]:
array([3, 4, 4, 5, 6, 6, 6])
The size of numpy arrays is immutable but you can create a copy of this array using this simple oneliner:
arr = np.array([2, 2, 3, 4, 4, 5, 6, 6, 6])
arr[arr!=np.min(arr)]
array([3, 4, 4, 5, 6, 6, 6])
You can get the indices that are greater than minimum value and slice the array as in this answer.
out = a[a>a.min()]
Notice this is faster than using np.delete as explained in the linked answer.
