Filter object values in array

Question

I have sorted array of objects:

const arr = [
    {
    "persentage": "30",
    "value": "123"
  },
  {
    "persentage": "27",
    "value": "345"
  },
  {
    "persentage": "2",
    "value": "232"
  },
    {
    "persentage": "2",
    "value": "343"
  },
  {
    "persentage": "9",
    "value": "4334"
  },
    {
    "persentage": "6",
    "value": "43343"
  },
    {
    "persentage": "4",
    "value": "95"
  },
];

I need to filter it by 2 conditions if sum of persentage will more 90+, I should skip other objects, or if count of objects is more then 6, then I also should skip rest of objects. I have next solution:

let arr2 = [];

const MAX_PESENTAGE = 90;
const MAX_TOP_VALUES = 6;

let accumulatePersentage = 0;
let countOfValue = 0;

for(const elem of arr) {
  accumulatePersentage += Number(elem.persentage);
  countOfValue++;
  if(accumulatePersentage >= MAX_PESENTAGE || countOfValue > MAX_TOP_VALUES) {
    break;
  }
  arr2.push(elem);
}
  
console.log(arr2)

But I am not sure is it best solution?

"best solution" is of course highly subjective. I'd say your solution does what it's supposed to do, is pretty clean - so don't care too much. — obscure
– obscure, Commented Sep 2, 2020 at 18:55
it s percentage not persentage that s the only thing you should change — EugenSunic
– EugenSunic, Commented Sep 2, 2020 at 18:57

Đinh Carabus · Accepted Answer · 2020-09-03 18:05:32Z

1

You could use reduce like this:

const arr = [
  { "persentage": "30", "value": "123" },
  { "persentage": "27", "value": "345" },
  { "persentage": "2", "value": "232" },
  { "persentage": "2", "value": "343" },
  { "persentage": "9", "value": "4334" },
  { "persentage": "6", "value": "43343" },
  { "persentage": "4", "value": "95" }
];

const filtered = arr.reduce((acc, item, i) => {
  acc.percentage += Number(item.persentage);
  if (acc.percentage <= 90 && i < 6) {
    acc.items.push(item);
  }
  return acc;
}, {percentage: 0, items: []}).items;

console.log(filtered);

edited Sep 3, 2020 at 18:05

answered Sep 2, 2020 at 19:01

Đinh Carabus

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