I have a couple of queries, detailed below. I'd like to be able to run one SQL query which returns both counts, is this possible?
1.
select nvl(count(rowid), 0) from tablename where OPP = 'FOO' and date = 'BAZ';
2.
select nvl(count(rowid), 0) from tablename where OPP = 'BAR' and date = 'BAZ';
I've only found MSSQL specific solutions in my searches so far.
If you need them in a single row:
SELECT
COUNT(CASE OPP WHEN 'FOO' THEN 1 END),
COUNT(CASE OPP WHEN 'BAR' THEN 1 END)
FROM tablename
WHERE OPP IN ('FOO', 'BAR') AND date = 'BAZ'
(The GROUP BY approach by Thilo is a better generic solution anyway.)
If the condition really looks like that (same table, only one field different in the groups):
select opp, count(*) from tablename
where date = 'BAZ'
group by opp
having opp in ('FOO', 'BAR');
For arbitrary queries:
select 'A', count(*) from tableA
union all
select 'B', count(*) from tableB
You could use a with statement:
with
count1 as (
select ...
),
count2 as (
select ...
)
select tot1, tot2
from count1, count2
