Missing placeholder for iOS SwiftUI TextField that inputs an Int

Question

I would like my iOS SwiftUI TextField to display the placeholder "Enter an integer:", but the TextField displays 0 (the value of the var value). The placeholder "Enter an integer:" does appear when the user deletes the 0. How can I get the placeholder "Enter an integer:" to appear without making the user delete the 0 first? Thank you in advance. Xcode 11.6 on macOS Catalina 10.15.6.

struct ContentView: View {
    @State private var value: Int = 0;
    @State private var text: String = "";
    
    var body: some View {
        VStack {
            TextField(
                "Enter an integer:",
                value: $value,
                formatter: NumberFormatter(),
                onCommit: {self.text = "The product is \(2 * self.value).";}
            )
            .keyboardType(.numbersAndPunctuation)
            .textFieldStyle(RoundedBorderTextFieldStyle())
            
            Text(text)
        }
        .padding([.leading, .trailing], 16)
    }
}

Asil ARSLAN · Accepted Answer · 2023-02-20 07:28:13Z

5

We need to use formatter to show placeholder.

Our formatter should have formatter.zeroSymbol = ""

let numberFormatter: NumberFormatter = {
    let formatter = NumberFormatter()
    formatter.numberStyle = .none
    formatter.zeroSymbol  = ""
    return formatter
}()

Using formatted:

TextField("Enter an integer:", value: $value, formatter: numberFormatter)
                    .keyboardType(.numbersAndPunctuation)

Happy Coding :)

edited Feb 20, 2023 at 7:28

answered Oct 24, 2022 at 20:22

Asil ARSLAN

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Asperi · Accepted Answer · 2020-08-17 09:08:00Z

3

To give placeholder with formatted TextField we need to use optional value holder.

Here is a fixed variant

struct ContentView: View {
    @State private var value: Int?
    @State private var text: String = ""

    var body: some View {
        VStack {
            TextField(
                "Enter an integer:",
                value: $value,
                formatter: NumberFormatter(),
                onCommit: {self.text = "The product is \(2 * (self.value ?? 0)).";}
            )
            .keyboardType(.numbersAndPunctuation)
            .textFieldStyle(RoundedBorderTextFieldStyle())

            Text(text)
        }
        .padding([.leading, .trailing], 16)
    }
}

answered Aug 17, 2020 at 9:08

Asperi

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