Is it possible to make the script drop everything it's been doing if a timer hits a certain time?
Let's say I want it to run for 24 hours and after that it should print a few things and then exit.
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1time.sleep(24*60*60)hostingutilities.com– hostingutilities.com2020-07-16 16:10:09 +00:00Commented Jul 16, 2020 at 16:10
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1 Answer
This is a pretty rude method but it will work. REMEMBER: put your code after the else statement or it won't work. Also, modify the comment above exit() as the comment said. PS.: this are built-in modules. No need to install anything.
import datetime
from sys import exit
starting_time = datetime.datetime.now()
while True:
actual_datetime = datetime.datetime.now()
if actual_datetime > starting_time + datetime.timedelta(days=1):
# do what you need to do before it shut down
exit()
else:
# RUN YOUR PROGRAM HERE
1 Comment
Lorenzo Paolin
Also, you can't use time.sleep() because it will only delay your current thread for a day and it won't tun your code in a "sort of parallel way"