Compare Object value with array?

Question

I want to compare the object with the given array, the object that I am using is mentioned below

var table = { api_key: "1234", data: [{ temperature: 100, humidity: 200 }] };

The array that I used is mention below :

var key = [ '1234', '3456' ]

the code that is used to return the object when the values of array and object api_key is equal mention below

const value = key.filter(val => {
      if(table.api_key === val){
     console.log({table})
     return [table];
     }
   });

but when I use that code am not getting the return value of that given object. How to return the object when the array value and object api_key values are same

I want to return the same object when condition satisfies example output:

{ api_key: "1234", data: [{ temperature: 100, humidity: 200 }] };

var table = { api_key: "1234", data: [{ temperature: 100, humidity: 200 }] };
var key = [ '1234', '345' ]

 const value = key.filter(val => {
      if(table.api_key === val){
     console.log({table})
     return [table];
     }
   }); 
   
   console.log({value})

What do you want exactly? It is unclear what you want as an output. — epascarello
– epascarello, Commented Jul 9, 2020 at 13:28

Rajneesh · Accepted Answer · 2020-07-09 13:42:21Z

1

You can create a method and pass the object and array to it and return accordingly. Something like this you can implement:

const table = { api_key: "1234", data: [{ temperature: 100, humidity: 200 }] };
const key = [ '1234', '3456' ];

const getObjectIfMatch = (obj, keyArr)=>keyArr.includes(obj.api_key) ? obj : {}

console.log(getObjectIfMatch(table, key));

answered Jul 9, 2020 at 13:42

Rajneesh

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Comments

Alexa DeWit · Accepted Answer · 2020-07-09 13:53:36Z

0

Given that you only have one possible "result" in that 'table', due to its nature of being a single object with only one field to determine the case...

You actually have a pretty simple case that doesn't require any complex composition

const tableKeyFound = keys.some(k => table.api_key === k)
const table = tableKeyFound ? [table] : []

answered Jul 9, 2020 at 13:53

Alexa DeWit

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Comments

Talha Noyon · Accepted Answer · 2020-07-09 14:26:46Z

0

I think this one is your desired answer

var table = { api_key: "1234", data: [{ temperature: 100, humidity: 200 }] };
var key = [ '1234', '3456' ]
function matchKeys(table){
    if(key.includes(table.api_key)){
        return table;
    }else {
        return "not found";
    }
}
console.log(matchKeys(table))

answered Jul 9, 2020 at 14:26

Talha Noyon

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