unable to check if string is substring of another in python

Sure, user_comment is not in comment_in_movie, you need to split user_comment by space then search for each word. Here is the solution:

  if all(x in comment_in_movie for x in user_comment.split(" ")):
    print ("found")

You answered is right by your own.Now you can solve this problem by many steps:

1. Store the string as a list with elements of that list equal to the words separated by spaces in the string and use a loop to check whether the elements of first string are present in the second string.But the problem with this method is that it is return true even if the elements of the first string are present in the second string even in the wrong order...Hope you got the answer.If you don't know about loops you can learn them from no. of tutorials present om different platforms or just text back.

You can split your

user_comment ="Hobbit 2013:Bad Movie"

Into two separate strings by using

user_comment = "Hobbit 2013:Bad Movie"
comment_in_movie = "Hobbit 2013 [email protected]:Bad Movie"
split_string = user_comment.split(":")
if split_string[0] in comment_in_movie and split_string[1] in comment_in_movie:
    print("found")

and then compare them to the:

comment_in_movie = "Hobbit 2013 [email protected]:Bad Movie"

Notice how this answer is different from the first one because you access the split text by list index.

You can do this, in order to test whether comment_in_movie contains all characters from user_comment in the correct order. Additional characters that are missing from user_comment are permitted anywhere inside comment_in_movie, and the loop over the characters of comment_in_movie will just carry on until it finds matching characters again. Provided that the end of user_comment is reached before running out of characters in comment_in_movie, that is considered a match.

user_comment = "Hobbit 2013:Bad Movie"
comment_in_movie = "Hobbit 2013 [email protected]:Bad Movie"

i = 0

for c in comment_in_movie:
    if user_comment[i] != c:
        continue
    i += 1
    if i == len(user_comment):
        found = True
        break
else:
    found = False

if found:
    print("found")

The above code makes no assumptions whatsoever regarding permitted places in which missing characters may occur. In some sense, this is more flexible because it checks that all characters are present, while not needing any advance knowledge of what delimiter(s) to use to split the string. However, it might be for example that gaps in the middle of a word should not be acceptable (e.g. if user_comment contained Hit instead of Hobbit).

For this reason, an alternative version is given below which is based on looking for whole words. All the words in user_comment now have to appear in comment_in_movie, again in the correct order, and non-word characters e.g. punctuation are simply ignored. The logic is exactly the same, except that we loop over words in lists, instead of characters in strings. So for example, "Hobbit 2013,Bad Movie" would be "found", without requiring that the comma is contained in comment_in_movie, but "Hit 2013:Bad Movie" would not be "found".

import re

user_comment = "Hobbit 2013:Bad Movie"
comment_in_movie = "Hobbit 2013 [email protected]:Bad Movie"

user_comment_words = re.findall("\w+", user_comment)
comment_in_movie_words = re.findall("\w+", comment_in_movie)

i = 0
for w in comment_in_movie_words:
    if user_comment_words[i] != w:
        continue
    i += 1
    if i == len(user_comment_words):
        found = True
        break
else:
    found = False

if found:
    print("found")