Sort Array of objects by number in specific order

Question

i have got the following array ob objects:

let given = [
{id: 1, number: 43},
{id: 2, number: 0},
{id: 3, number: 3},
{id: 4, number: undefined},
{id: 5, number: 1},
{id: 6, number: 0},
{id: 7, number: 0},
{id: 8, number: 36},
{id: 69, number: 0}
]

and want to sort it in this way

let expected = [
{id: 1, number: 43},
{id: 3, number: 3},
{id: 4, number: undefined}, 
{id: 5, number: 1},
{id: 8, number: 36},
{id: 2, number: 0},
{id: 6, number: 0},
{id: 7, number: 0},
{id: 69, number: 0}
]

all objects with 0 number should be in the end of the array but the previous order should still exist

i tried array.sort() but have not received the desired result

Yury Tarabanko · Accepted Answer · 2020-06-03 13:21:34Z

2

You first filter non-zero objects, than zero objects. Then concat both arrays.

let given = [
{id: 1, number: 43},
{id: 2, number: 0},
{id: 3, number: 3},
{id: 4, number: undefined},
{id: 5, number: 1},
{id: 6, number: 0},
{id: 7, number: 0},
{id: 8, number: 36},
{id: 69, number: 0}
]

const expected = [
  ...given.filter(item => item.number !== 0),
  ...given.filter(item => item.number === 0)
]

console.log(JSON.stringify(expected))

Or you could use a single loop if you think two loops might affect your app performance.

answered Jun 3, 2020 at 13:21

Yury Tarabanko

45.1k10 gold badges88 silver badges99 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Nina Scholz · Accepted Answer · 2020-06-03 13:26:47Z

2

You could sort with the delta of the check with zero.

let given = [{ id: 1, number: 43 }, { id: 2, number: 0 }, { id: 3, number: 3 }, { id: 4, number: undefined }, { id: 5, number: 1 }, { id: 6, number: 0 }, { id: 7, number: 0 }, { id: 8, number: 36 }, { id: 69, number: 0 }];

given.sort(({ number: a }, { number: b }) => (a === 0) - (b === 0));

console.log(given);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Jun 3, 2020 at 13:26

Nina Scholz

388k26 gold badges367 silver badges417 bronze badges

Comments

felixmosh · Accepted Answer · 2020-06-03 13:27:01Z

1

You can split your given array into 2, zeros & noneZeros while remaining the original order with Array.reduce.

let given = [
  {id: 1, number: 43},
  {id: 2, number: 0},
  {id: 3, number: 3},
  {id: 4, number: undefined},
  {id: 5, number: 1},
  {id: 6, number: 0},
  {id: 7, number: 0},
  {id: 8, number: 36},
  {id: 69, number: 0},
];

const x = given.reduce(
  (result, item) => {
    if (item.number === 0) {
      result.zeros.push(item);
    } else {
      result.noneZeros.push(item);
    }
    return result;
  },
  {zeros: [], noneZeros: []}
);

console.log(x.noneZeros.concat(x.zeros));

answered Jun 3, 2020 at 13:27

felixmosh

35.8k10 gold badges81 silver badges99 bronze badges

Comments

janmbaco · Accepted Answer · 2020-06-03 13:25:36Z

0

You can do this with two arrays

let given = [
{id: 1, number: 43},
{id: 2, number: 0},
{id: 3, number: 3},
{id: 4, number: undefined},
{id: 5, number: 1},
{id: 6, number: 0},
{id: 7, number: 0},
{id: 8, number: 36},
{id: 69, number: 0}
]
var a = []; 
var b = [];
for(let data of given){
	if(data.number == 0){
  	a.push(data)
  } else {
  	b.push(data)
  }
}
var c = b.concat(a);
console.log(c)

answered Jun 3, 2020 at 13:25

janmbaco

3495 silver badges12 bronze badges

Comments

Michael Mishin · Accepted Answer · 2020-06-03 13:27:06Z

0

Use sort with callback function:

given.sort((a,b) => b.number === 0 && a.number !== 0 ? -1 : 0);

answered Jun 3, 2020 at 13:27

Michael Mishin

5713 silver badges8 bronze badges

Comments

Rajib · Accepted Answer · 2020-06-03 13:30:17Z

0

let given = [
  { id: 1, number: 43 },
  { id: 2, number: 0 },
  { id: 3, number: 3 },
  { id: 4, number: undefined },
  { id: 5, number: 1 },
  { id: 6, number: 0 },
  { id: 7, number: 0 },
  { id: 8, number: 36 },
  { id: 69, number: 0 },
];

var zeroarray = given.filter((val) => {
  if (val.number === 0) return val;
});

var nonzeroarray = given.filter((val) => {
  if (val.number != 0) return val;
});
var final=[...nonzeroarray,...zeroarray];
 console.log(final);

answered Jun 3, 2020 at 13:30

Rajib

244 bronze badges

Comments

Guilherme Branco · Accepted Answer · 2020-06-03 13:32:59Z

0

let given = [
{id: 1, number: 43},
{id: 2, number: 0},
{id: 3, number: 3},
{id: 4, number: undefined},
{id: 5, number: 1},
{id: 6, number: 0},
{id: 7, number: 0},
{id: 8, number: 36},
{id: 69, number: 0}
]

var arr = []

for(var i = 0; i < given.length; i++){
  if(given[i].number === 0){
    arr.push(given[i]);
  }
}

given = given.filter(item => item.number !== 0);

given = given.concat(arr)

console.log(given)

answered Jun 3, 2020 at 13:32

Guilherme Branco

311 silver badge4 bronze badges

Collectives™ on Stack Overflow

Sort Array of objects by number in specific order

7 Answers 7

Comments

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

7 Answers 7

Comments

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related