Typescript - Missing initializer in const declaration

Question

I have below code. Getting error SyntaxError: Missing initializer in const declaration

const manufacturers: any[] = [];        
console.log('Available Products are: ');
for (const item of manufacturers) {
     console.log(item.id);
}

if I change declaration to const manufacturers= []; code works fine, but VSCode shows warning "Variable 'manufacturers' implicitly has type 'any[]' in some locations where its type cannot be determined.

I am using node js v12.16.1 and typescript : ^2.5.3

Can't reproduce this error on TypeScript versions going back as far as 2.4.1. — Robby Cornelissen
– Robby Cornelissen, Commented May 7, 2020 at 5:52

wentjun · Accepted Answer · 2020-05-07 06:37:07Z

3

You need to declare an interface for manufacturers, as TypeScript won't be able infer the properties for typechecking if you use any:

interface Manufacturer {
  id: string;
  // add other properties
}

const manufacturers: Manufacturer[] = [];

answered May 7, 2020 at 6:37

wentjun

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5 Comments

Rajeshree Nevare Over a year ago

Why need to declare interface ? I need an array of type Any. const manufacturers: any[] = [ {id =101 , name = 'test 1'}, {id =102 , name = 'test 2'}];

wentjun Over a year ago

Either you use an interface, or you declare it with any. I highly recommend interface because TypeScript needs it for typechecking.

wentjun Over a year ago

@RajeshreeNevare hey, did my answer solve your issue?

Rajeshree Nevare Over a year ago

Yes, Declaring interface will work. But any is not working. I have suppressed strict type checking from tsconfig.json file

wentjun Over a year ago

Yeahh good call. You should limit the use of any due to my above point

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