modify the object values based on array of strings

Question

I have tried my best the whole day but I can't find a working solution for my problem.

Here is it.

I have an object containing the list of folders and the number of files inside each one like this:

let Folders = {

  'listen': 0,
  'listen_again_long': 0,
  'intercations': 0,
  'watch_again': 0,

};

And an array named result that contains the list of files inside the parent folder of above object.

let result = [

"https://example.com/test/media/instructions/listen/1.mp3",
"https://example.com/test/media/instructions/listen/2.mp3",

"https://example.com/test/media/instructions/listen_again_long/1.mp3",
"https://example.com/test/media/instructions/listen_again_long/2.mp3",
"https://example.com/test/media/instructions/listen_again_long/3.mp3",
"https://example.com/test/media/instructions/listen_again_long/4.mp3",

"https://example.com/test/media/instructions/watch_again/1.mp3",

]

I want to count the files inside each folder (listen...listen_again_long...) based on information represented in result array and modify the numbers of Folders object...

For instance in the above sample codes we have 2 files inside listen and 4 inside listen_again_long and 1 inside watch_again and none in intercations. so we should get back the object like this:

let Folders = {

  'listen': 2,
  'listen_again_long': 4,
  'intercations': 0,
  'watch_again': 1,

};

Michał Z. · Accepted Answer · 2020-05-05 17:31:27Z

1

This might work:

let Folders = {
  'listen': 0,
  'listen_again_long': 0,
  'intercations': 0,
  'watch_again': 0,
};


let result = [
  "https://example.com/test/media/instructions/listen/1.mp3",
  "https://example.com/test/media/instructions/listen/2.mp3",

  "https://example.com/test/media/instructions/listen_again_long/1.mp3",
  "https://example.com/test/media/instructions/listen_again_long/2.mp3",
  "https://example.com/test/media/instructions/listen_again_long/3.mp3",
  "https://example.com/test/media/instructions/listen_again_long/4.mp3",

  "https://example.com/test/media/instructions/watch_again/1.mp3"
]

function updateFoldersCount(urls, folders){
  urls.forEach(v => {
    const folder = v.match(/instructions\/(.+)\//)[1]; // assuming that it will always be like ...instructions/{folder name}/...
    folders[folder] = folders[folder] ? folders[folder]+1 : 1; // in case of folder doesn't exist yet - it will create it
  });
}

updateFoldersCount(result, Folders);

console.log(Folders)

edited May 5, 2020 at 17:31

answered May 5, 2020 at 17:17

Michał Z.

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2 Comments

foxer Over a year ago

Thanks for the answer. what if the folder names changes to listen: 0, listen_again_last: 0, listen_again_long: 0, listen_again_short: 0,

foxer Over a year ago

And ` 'lets_start': 0, 'try_again': 0, 'interact_again': 0,`

brk · Accepted Answer · 2020-05-05 17:05:52Z

0

Iterate the object & check if the key like folderA,folderB is contained in any string from the result array. You can get the count of the strings which contains the keys bu using filter & length. Also instead of mutating the existing object inside a loop create a new object and assign the key & count

let folders = {

  'folderA': 0,
  'folderB': 0,
  'folderC': 0,
  'folderD': 0,

}

let result = [
  "https://example.com/test/media/instructions/folderA/1.mp3",
  "https://example.com/test/media/instructions/folderA/2.mp3",

  "https://example.com/test/media/instructions/folderB/1.mp3",
  "https://example.com/test/media/instructions/folderB/2.mp3",
  "https://example.com/test/media/instructions/folderB/3.mp3",
  "https://example.com/test/media/instructions/folderB/4.mp3",

  "https://example.com/test/media/instructions/folderD/1.mp3",
];

let newFolder = {};

for (let keys in folders) {
  let getCount = result.filter(item => item.includes(keys)).length
  newFolder[keys] = getCount
}

console.log(newFolder)

answered May 5, 2020 at 17:05

brk

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3 Comments

foxer Over a year ago

Thanks for the answer.. that is exactly what I've done before... maybe I should change the examples to show you the problem... I don't want to simply use includes because these folders will be count together listen: 0, listen_again_last: 0, listen_again_long: 0, listen_again_short: 0,

brk Over a year ago

Then use String.match

brk Over a year ago

@foxer stackoverflow.com/questions/5752829/…

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