Why does my code work when run in .py file, but returns a SyntaxError in Python interpreter?

Question

Consider this code:

with open("tmp", "w") as f:
    print(0)
print(1)

This works when saved as bug.py and run with python bug.py. But I can't copy and paste this code into a python interpreter:

Python 3.8.2 (tags/v3.8.2:7b3ab59, Feb 25 2020, 23:03:10) [MSC v.1916 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> with open("tmp", "w") as f:
...     print(0)
... print(1)
  File "<stdin>", line 3
    print(1)
    ^
SyntaxError: invalid syntax
>>>

Where's the syntax error?

Edit: This applies more generally, as in

if False:
    pass
pass

lenik · Accepted Answer · 2020-05-04 06:24:44Z

6

You need an extra empty line to end up your with statement and input the next print statement:

>>> with open('/dev/random') as fin :
...     print(0)
...                             <<--- an empty line
0
>>> print(1)
1
>>>

answered May 4, 2020 at 6:24

lenik

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2 Comments

Luv Over a year ago

Any loop should be closed in the interactive mode by pressing <Return> twice before any other statement.

bers Over a year ago

Is there any way I could have known that? ;)

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