Find and Return an object from an array of array of objects using a property value

Question

I have an array of array of objects. Is there an ES6 way to find and return an object based on a property value?

const tempArray = [];
tempArray.push([{ name: 'apple', y: 1}, { name: 'orange', y: 2}]);
tempArray.push([{ name: 'pear', y: 3}]);

Given the value property name of 'apple', I want the object { name: 'apple', y: 1} returned.

I've tried tempArray.filter(k => k.some(e => e.name === 'apple')) but it returns an array of array of objects which I don't want.

Thanks for your help in advance,

You do have an array of array of objects. Why not maintain a single level array in the first place? — VLAZ
– VLAZ, Commented Apr 28, 2020 at 22:29

CertainPerformance · Accepted Answer · 2020-04-28 22:28:25Z

1

Flatten the array, then use .find to find the matching object:

const tempArray = [];
tempArray.push([{ name: 'apple', y: 1}, { name: 'orange', y: 2}]);
tempArray.push([{ name: 'pear', y: 3}]);

const obj = tempArray.flat().find(({ name }) => name === 'apple');
console.log(obj);

answered Apr 28, 2020 at 22:28

CertainPerformance

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