I don't get how a "for" loop that iterates through the elements of a list can be out of range. First part seems to be okay as I can print it.
import random
def random_list(n):
l = []
for i in range(0,n):
l.append(random.randint(0,n))
return l
def maximum(n):
x = 0
b = random_list(n)
for i in b:
if b[i] > x:
x = b[i]
print (maximum(10))
This:
for i in b:
if b[i] > x:
x = b[i]
Iterates over the elements of b, not the indices. Change it to
for i in b:
if i > x:
x = i
You also need to return something from your function, probably x.
for i in b iterates over the elements. Compare that to for index in range(len(b)):. Also, you need to return something from your function (probably x).Considering that you know how to iterate over a list in python, the error could be due to randint, which generates an integer in the interval [low, high]. This means high is a possible output, while the highest index in your program is high - 1.
For example,
random.randint(0, 0)
gives 0.
Similarly, random.randint(10) can return 10.
If you don't understand how to iterate over a list in Python, consider a simple example:
Take the list below:
myList = [1, 3, 5, 7, 9]
Now, there are two ways to iterate over the list:
Directly accessing elements:
for element in myList:
print(element, end=" ")
This gives the output:
1 3 5 7 9
Accessing elements using indices
for idx in range(len(myList)):
print(idx, ":", myList[idx], end=" ")
This gives the output:
0:1 1:3 2:5 3:7 4:9
enumerate.
randint includes n as a possible generated number; its range is 0(inclusive) to n(inclusive). https://stackoverflow.com/questions/2568783/python-why-does-random-randinta-b-return-a-range-inclusive-of-b